Bash script preserve command-line arguments

If we want to preserve (pass) the command line arguments when running a bash script and pass them to a program defined in the script, we can use the $* pattern after the call. An example bash script called myscript.sh is shown below. It sets some environment variables (optional) and starts a program called myserver. The program will accept all command line args passed to the bash script as if they were passed to the myserver program directly.

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#!/bin/bash

SOME_ENV_VARIABLE=var1 \
ANOTHER_ENV_VARIABLE=var2 \
myserver $*

Calling the script like:

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./myscript.sh -addr http://example.com -port 8080

will be like calling the myserver program like:

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./myserver -addr http://example.com -port 8080